birt code 128

birt code 128

birt code 128

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We ll start with the trace event I set in the very first test the CBO or 10053 trace. When I had a manual workarea_size_policy, a sort_area_size of 1MB, and CPU costing disabled, the critical sections of the trace file look like this: SINGLE TABLE ACCESS PATH TABLE: T1 ORIG CDN: 1048576 ROUNDED CDN: 1048576 Access path: tsc Resc: 266 Resp: 266 BEST_CST: 266.00 PATH: 2 Degree: 1 CMPTD CDN: 1048576

To create a new account, follow these steps:

R^ r; (Object^) r; const int i; const_cast<int>(i);

Join order[1]: T1[T1]#0 ORDER BY sort SORT resource Sort statistics Sort width: 29 Area size: 712704 Max Area size: 712704 Degree: 1 Blocks to Sort: 2311 Row size: 18 Rows: 1048576 Initial runs: 27 Merge passes: 1 IO Cost / pass: 2711 Total IO sort cost: 2511 Total CPU sort cost: 0 Total Temp space used: 33711000 Best so far: TABLE#: 0 CST: 2777 CDN: 1048576 BYTES: 7340032

1. 2.

I have included the single-table access path in the extract to show you the cost of the full tablescan (266) that Oracle used to acquire the data that was to be sorted The last line printed shows the best cost so far as 2,777, which is the sum of 266 (the tablescan cost) and 2,511 (the Total IO sort cost) We need to understand how the optimizer derives the value 2,511 for the Total IO sort cost Before getting into the difficult bits, I d like to explain the other numbers that appear in the second section of the output In order: Sort width: This is the same as the max intermediate sort width we saw in the 10032 trace Area size: This is the amount of memory available for processing the data Our sort_area_size was 1MB, so the size reported here seems a little small.

In the 8i-style calculations, the optimizer allows 10% (rounded to an exact multiple of the block size) of the sort_area_size for write buffers This still leaves a lot missing which according to my theory is the allowance built into the model for the binary insertion tree Subtract 10% (rounded to the next complete block) from the initial value, and then subtract 25% of the rest for the sort tree: 1,048,576 bytes = 128 blocks (at 8KB); subtract 13 blocks (10%) and you get 115 blocks; subtract 25%, and you get 8625 blocks rounding up to the nearest block this is 87 blocks 712,704 bytes, which is what we see here Note, however, that this 25% allowance does not change as the row size changes (which it probably ought to if my theory were correct); nor does it change as you move from 32-bit Oracle to 64-bit Oracle.

Evaluates to another type of cast. Can only remove or add const (or volatile).

Click the Create New Account button at your provider s site. You see a Legal Agreement. In order to continue, check the I have read this agreement box and click the I Agree button. After accepting the legal agreement, you should see a screen (see Figure 1-8).

Max Area size: Since this is a 9i trace file, the Area size reports the minimum allocation size available based on the setting of the pga_aggregate_target, and the Max area size reports the maximum area that the session will be allowed Since this test case is running 8i-style, using the manual workarea size policy, the Area size and Max area size are identical When the two values differ, the calculation of cost seems to be based on the Max area size, rather than the Area size Degree: If you are allowing parallel execution, you will get two completely separate, identically structured sections of trace file showing the cost calculations for the sort.

Both of the numbers you need are under your Options icon on your BlackBerry. Click the Options icon, and press the letter S on your keyboard a few times until you get to the Status item and click it. Once in Status, look at the lines marked PIN and IMEI shown in Figure 1-9.